percentages Model Questions & Answers, Practice Test for ibps rrb po prelims
60% of $8{1}/4 + 6/5 = 15 - ?$
Answer: (b)
$15 - 6/5 - 60% of 8{1}/4$
= 13.8 - $60/100 × 33/4$
= 13.80 - 4.95 = 8.85
If the price of sugar is increased by 7%, then by how much per cent should a housewife reduce her consumption of sugar, to have no extra expenditure ?
Answer: (c)
% reduction in consumption
= ${% \text"change in price"}/{100 + % \text"change in price"} × 100$
= $7/{100 + 7} % = 7/107 %$
What is the value of 280% of 460?
Answer: (b)
Required answer = 460 × $280/100$ = 1288
The income of A is 150% of the income of B and the income of C is 120% of the income of A. If the total income of A, B and C together is Rs. 86000, what is C’s income ?
Answer: (a)
Suppose Income of B = Rs. x
Income of A = $150/100 × x = Rs. {3x}/2$
Income of C = $120/100 × {3x}/2$
$6/5 × {3x}/2 = {9x}/5$
∴ $x + {3x}/2 + {9x}/5 = 86000$
${10x + 15x + 18x}/10 = 86000$
43x = 860000
x = 20000
So, income of C = $9/5 × 20000$ = Rs. 36000
If the numerator of a fraction is increased by 200% and the denominator is increased by 160%, the resultant fraction is $7/13$. What is the original fraction?
Answer: (b)
Let the original fraction = $x/y$
According to the question,
${{300x}/100}/{{260y}/100} = 7/13$
or ${30x}/{26y} = 7/13$
∴ $x/y = 7/13 × 26/30 = 7/15$
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